题目:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int Search(int val,int &l,int &r) {
for(int i = l;i = n || l > r) return;
root = new TreeNode(preorder[pos]);
int id = Search(preorder[pos++],l,r);
dfs(root->left,l,id-1);
dfs(root->right,id+1,r);
}
TreeNode* buildTree(vector& preorder, vector& inorder) {
this->preorder = preorder;
this->inorder = inorder;
n = inorder.size();
if(!n) return nullptr;
pos = 0;
TreeNode *root;
dfs(root,0,n-1);
return root;
}
private:
vector preorder;
vector inorder;
int pos,n;
};