题目链接
https://www.acwing.com/problem/content/2062/
思路先DFS染色,将这两部分分开,分别用1和2标记,然后对于第一堆的每个元素直接用BFS跑一个最短路即可
代码#include
using namespace std;
#define endl "\n"
const int N = 100;
char mp[N][N];
int a[N][N];
int n,m;
int dx[4]={-1,1,0,0};
int dy[4]={0,0,-1,1};
bool vis[N][N];
bool check(int x,int y) {
if(x >= 1 && x = 1 && y >m;
for(int i = 1;i mp[i][j];
}
}
int k = 1;
for(int i = 1;i
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