1051 Pop Sequence (25 分)
#include
using namespace std;
const int N = 1e5+10;
int n, m, k;
int a[N], b[N];
int main()
{
cin >> m >> n >> k;
for (int i = 1;i b[i];
for (int i = 1, j = 1;i m) break;
while (stk.size() && j > n >> head;
for (int i = 0;i > add >> key >> nxt;
node[i] = {key, add};
a[add] = nxt;
}
int p = head;
while (p != -1) {
st[p] = 1;
p = a[p];
}
sort (node, node+n);
for (int i = 0;i amin >> amax;
cout
关注
打赏