您当前的位置: 首页 >  光怪陆离的节日 c#

C#实现图的深度优先遍历递归算法--详细代码

光怪陆离的节日 发布时间:2022-06-30 16:20:07 ,浏览量:3

本文测试C#实现图的深度优先遍历递归算法–详细代码
1、代码如下:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace 图的应用__深度优先搜索算法
{
using VertexType = System.Char;//顶点数据类型别名声明
using EdgeType = System.Int16;//带权图中边上权值的数据类型别名声明
class Program
{
public const int MAxVertexNum = 100;//顶点数目的最大值
public const int MAXSize = 100;
static void Main(string[] args)
{
MGraph G = new MGraph();
int u;
int[] d = new int[MAxVertexNum];
G.vexnum = 8;
G.arcnum = 8;
G.vex = new VertexType[MAxVertexNum];
G.Edge = new EdgeType[MAxVertexNum, MAxVertexNum];
for (int i = 0; i < MAxVertexNum; ++i)
{
for (int j = 0; j < MAxVertexNum; ++j)
{
G.Edge[i, j] = 0;
}
}
//图的赋值
G.vex[0] = ‘a’; G.vex[1] = ‘b’; G.vex[2] = ‘c’; G.vex[3] = ‘d’; G.vex[4] = ‘e’; G.vex[5] = ‘f’;
G.vex[6] = ‘g’; G.vex[7] = ‘h’;
G.Edge[0, 1] = 1; G.Edge[0, 2] = 1;
G.Edge[1, 0] = 1; G.Edge[1, 3] = 1; G.Edge[1, 4] = 1;
G.Edge[2, 0] = 1; G.Edge[2, 5] = 1; G.Edge[2, 6] = 1;
G.Edge[3, 1] = 1;
G.Edge[4, 1] = 1; G.Edge[4, 7] = 1;
G.Edge[5, 2] = 1;
G.Edge[6, 2] = 1;
G.Edge[7, 4] = 1;
Console.WriteLine(“深度优先:”);
DFS_Traverse(G);
Console.ReadLine();
}

    /// 
    /// 图的定义--邻接矩阵
    /// 
    public struct MGraph
    {
        public VertexType[] vex;//顶点表数组
        public EdgeType[,] Edge;//临接矩阵、边表
        public int vexnum, arcnum;//图的当前顶点数和弧数
    }
    /// 
    /// 图的定义--邻接表法
    /// 
    public class ArcNode
    {//边表节点
        public int adjvex;
        public ArcNode next;
    }
    public class VNode
    {  //顶点表节点
        VertexType data;//顶点信息
        ArcNode first;//只想第一条依附改顶点的弧的指针
    }
    public class ALGraph
    {
        VNode[] vertices;   //邻接表
        int vexnum, arcnum;//图的顶点数和弧数
    }
    /// 
    /// 深度优先搜索的递归实现
    /// 
    /// 
    /// 
    /// 
    static void DFS_Traverse(MGraph G) {
        bool[] visited = new bool[MAxVertexNum];
        for (int i=0;i            
关注
打赏
查看更多评论