1. 忘记密码页面展示
1.在users.views.py文件中定义视图
from django.views import View
class ForgetPasswordView(View):
def get(self, request):
return render(request, 'forget_password.html')
2.在users.urls.py文件中定义路由
from users.views import ForgetPasswordView
urlpatterns = [
# 参数1:路由
# 参数2:视图函数
# 参数3:路由名,方便通过reverse来获取路由
path('forgetpassword/', ForgetPasswordView.as_view(),name='forgetpassword'),
]
3.修改forget_password.html中的资源加载方式
{% load staticfiles %}
...
...
4.修改login.html中的忘记密码的跳转连接
忘记密码?
2. 忘记密码接口设计
1.请求方式
选项方案请求方法POST请求地址/forgetpassword/2.请求参数:表单
参数名类型是否必传说明mobilestring是用户名passwordstring是密码password2string是确认密码sms_codestring是短信验证码3.响应结果:HTML
字段说明修改失败响应错误提示修改成功重定向到登录 3. 忘记密码接口实现class ForgetPasswordView(View):
def post(self, request):
# 接收参数
mobile = request.POST.get('mobile')
password = request.POST.get('password')
password2 = request.POST.get('password2')
smscode = request.POST.get('sms_code')
# 判断参数是否齐全
if not all([mobile, password, password2, smscode]):
return HttpResponseBadRequest('缺少必传参数')
# 判断手机号是否合法
if not re.match(r'^1[3-9]\d{9}$', mobile):
return HttpResponseBadRequest('请输入正确的手机号码')
# 判断密码是否是8-20个数字
if not re.match(r'^[0-9A-Za-z]{8,20}$', password):
return HttpResponseBadRequest('请输入8-20位的密码')
# 判断两次密码是否一致
if password != password2:
return HttpResponseBadRequest('两次输入的密码不一致')
# 验证短信验证码
redis_conn = get_redis_connection('default')
sms_code_server = redis_conn.get('sms:%s' % mobile)
if sms_code_server is None:
return HttpResponseBadRequest('短信验证码已过期')
if smscode != sms_code_server.decode():
return HttpResponseBadRequest('短信验证码错误')
# 根据手机号查询数据
try:
user = User.objects.get(mobile=mobile)
except User.DoesNotExist:
# 如果该手机号不存在,则注册个新用户
try:
User.objects.create_user(username=mobile, mobile=mobile, password=password)
except Exception:
return HttpResponseBadRequest('修改失败,请稍后再试')
else:
# 修改用户密码
user.set_password(password)
user.save()
# 跳转到登录页面
response = redirect(reverse('users:login'))
return response
运行效果: